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How do I? : Control Positioning of Subform when switching?

thefarg (Programmer) (OP)
29 Jan 12 15:12
I have a form with a subform frame in it. Using

CODE

Me.MySubformFrame.Form = "MySubForm1"
works but the subform open outside of the frame. Top left corner in fact. Any ideas on why this is happening and how I can solve it?

Thanks
       Mike
thefarg (Programmer) (OP)
29 Jan 12 15:45
Currently, Im using the following code as a workaround.

CODE


Dim SubformTop As String
Dim SubformLeft As String
SubformLeft = sbfSalesPivot.Left
SubformTop = sbfSalesPivot.Top

            Me.sbfSalesPivot.Form.Visible = False
            Me.sbfSalesPivot.SourceObject = "frmHome_SalesAnalysisSubform4"
            sbfSalesPivot.Top = SubformTop
            sbfSalesPivot.Left = SubformLeft
            Me.sbfSalesPivot.Form.Visible = True
It appears to work fine, but its a messy way to do it. Can anyone help with the problem of the subform escaping its frame?
            sldGraph.Tag = 4
dhookom (Programmer)
29 Jan 12 23:19
thefarg,
Again unconventional request without providing context. I have never heard of a subform changing Top and Left properties without code changing them.

I would expect you should be using:

CODE

Me.MySubformFrame.SourceObject = "MySubForm1"
The top and left properties are numeric, not strings. Try to conform like:

CODE

Dim lngSubformTop As Long
Dim lngSubformLeft As Long
lngSubformLeft = Me.sbfSalesPivot.Left
lngSubformTop = Me.sbfSalesPivot.Top

Duane
Hook'D on Access
MS Access MVP

thefarg (Programmer) (OP)
30 Jan 12 18:18
Ok. Any idea why the subform moves? Im just trying to switch the graph on the main form "Home" on the Northwind 2007 db.

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