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list vs. dict : how to rearrange indices after removing element?

list vs. dict : how to rearrange indices after removing element?

list vs. dict : how to rearrange indices after removing element?

(OP)
With lists, when you delete one element the indices are rearranged, e.g. deleting "zero" from "zero one two" gives lindex 0 = "one". Is that possible with [dict create 0 "zero" 1 "one" ...] ? ( something like PHP's array_splice )

RE: list vs. dict : how to rearrange indices after removing element?

Hi

Not sure what is your goal and what you want with the dict.

If you just want to keep the original indices unchanged after deleting an element, use an array :

CODE --> tclsh

% array set whatever { 0 zero 1 one 2 two }

% array get whatever
0 zero 1 one 2 two

% array unset whatever 0

% array get whatever
1 one 2 two
 

Feherke.

RE: list vs. dict : how to rearrange indices after removing element?

(OP)
Thanks for replying :) It's quite the opposite, I need the keys to readjust themselves like list indices do, so if you delete key x then key x+1 becomes key x, and key x+2 becomes key x+1, etc.

RE: list vs. dict : how to rearrange indices after removing element?

Hi

Got you. At least, got your goal.

Sorry, I know no way to do that directly.

Maybe if you describe the task itself, someone will be know an alternative.
 

Feherke.

RE: list vs. dict : how to rearrange indices after removing element?

(OP)
Yeap, I thought it wasn't possible right out-of-the-box, but I was hoping I could spare myself nested lists and custom code. XD
Thank you anyway :)

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