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kurie (Programmer)
30 Jun 08 8:04
Can someone please help me by explaining why this statement returns an error mesaage in vb. the digits are also double variables
dim a as double

a = 446763600000  mod 31536000
returning overflow
Thank you
Helpful Member!  Golom (Programmer)
30 Jun 08 9:29
The Mod operator or the integer division operator "\" will produce an overflow if either operand is larger than 231 - 1 = 2,147,483,647.

You need to do it this way

CODE

446763600000 - Int(446763600000/31536000) * 31536000
kurie (Programmer)
1 Jul 08 7:39
Thank you very much, it worked

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