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ovince (Programmer) (OP)
19 Apr 07 2:40
hi All,

I would like to delete 2 columns from 60 columns data. How to do that except to write

awk '{print $1, $2 .... $60}' file.dat > newFile.dat

leaving out columns that I dont want in a newFile.dat?

feherke (Programmer)
19 Apr 07 3:18

If you do not care about the separators which will remain in place :


awk '{$40=$50=""}1' file.dat > newFile.dat
Or a less nice code with nicer output, although all field separators will be set to OFS :


awk '{for(i=1;i<=NF;i++)if(i!=40&&i!=50)printf$i OFS;print""}' file.dat > newFile.dat
Or we just can modify abit the first code to replace multiple field separators with one :


awk '{$40=$50="";gsub(FS "+",FS)}1' file.dat > newFile.dat
In my examples I removed columns 40 and 50.


Ygor (Programmer)
19 Apr 07 4:25
Unless you have to use awk, perhaps consider using cut, e.g...


cut -f-39,41-49,51- file.dat > newFile.dat
ovince (Programmer) (OP)
19 Apr 07 4:59

I have a csv file and I would like to keep like that. This try does not work if I want to remuve 1 column (i.e it leaves ',' in front of lines)

awk 'BEGIN{FS=",";OFS=","}{$1=$6="";gsub(FS "+",FS)}1' file.dat > newFile.dat

Feherke's suggestion is OK

ovince (Programmer) (OP)
19 Apr 07 5:03
sory...Ygor's suggestion with cut works and

awk 'BEGIN{FS=",";OFS=","}{$1=$6="";gsub(FS "+",FS)}1' file.dat > newFile.dat

leave ',' in front of each line
feherke (Programmer)
19 Apr 07 5:08

Right. I just wondered how could it be possible. :)

I completely ignored the situation of removing the first or the last field. For those the shell itself is enough.


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