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Windows Scripting

How to unzip files using Shell.application by mgagnon
Posted: 6 May 04 (Edited 16 May 05)

Note this requires Windows XP or higher

This was posted on a French newsgroup by Thierry (unknown last name)

Zip files

* The directories must be valid

CODE

cFileZip = "C:\temp2\D401001F.ZIP"
cSource = "c:\temp1\"
strtofile(chr(0x50)+chr(0x4B)+chr(0x05)+chr(0x06)+replicate(chr(0),18),cFileZip)
o=CREATEOBJECT("shell.application")
FOR EACH ofile IN o.NameSpace(cSource).items
   o.NameSpace(cFileZip).copyhere(ofile)
ENDFOR


Unzip files

CODE

cFileZip = "C:\temp\D401001F.ZIP"
cDestination = "c:\temp\"

o=CREATEOBJECT("shell.application")
FOR EACH ofile IN o.NameSpace(cFileZip).items
    o.NameSpace(cDestination).copyhere(ofile)
ENDFOR


Mike Gagnon

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